6x^2-35x=-49

Solution for 6x^2-35x=-49 equation:

6x^2-35x=-49

We move all terms to the left:

6x^2-35x-(-49)=0

We add all the numbers together, and all the variables

6x^2-35x+49=0

a = 6; b = -35; c = +49;
Δ = b2-4ac
Δ = -352-4·6·49
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-7}{2*6}=\frac{28}{12}
=2+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+7}{2*6}=\frac{42}{12}
=3+1/2
$